22 lines
347 B
Python
22 lines
347 B
Python
#Power digit sum
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#Problem 16
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#
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#215 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
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#
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#What is the sum of the digits of the number 21000?
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pp = 1000
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c = [0 for i in range(0, pp//3+1)]
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c[0] = 1
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for i in range(0,pp):
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r = 0
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for j in range(0,len(c)):
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p = c[j]*2+r
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r = p//10
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c[j] = p%10
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print( sum(c) )
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