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<h2>Perfection Quotients</h2><div class="info" style="cursor:help;width:200px;margin-bottom:10px;"><h3>Problem 241</h3><span style="width:300px;color:#666;">Published on Saturday, 18th April 2009, 02:00 am; Solved by 545</span></div>
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<p>For a positive integer <var>n</var>, let &sigma;(<var>n</var>) be the sum of all divisors of <var>n</var>, so e.g. &sigma;(6) = 1 + 2 + 3 + 6 = 12.
</p>
<p>A perfect number, as you probably know, is a number with &sigma;(<var>n</var>) = 2<var>n</var>.</p>
<p><div style='text-align:left;'>
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<td>Let us define the <b>perfection quotient</b> of a positive integer as</td><td><var>p</var>(<var>n</var>)</td><td>=&nbsp;</td>
<td><div style='text-align:center;'>&sigma;(<var>n</var>)<br /><img src='images/blackdot.gif' width='30' height='1' alt='' /><br /><var>n</var></div></td>
<td>.</td>
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</p>
<!--
<p>Let us define the <b>perfection quotient</b> of a positive integer as <var>p</var>(<var>n</var>) = <font "size=4"> <sup>&sigma;(<var>n</var>)</sup>&frasl;<sub><var>n</var></sub></font>.</p>
-->
<p>Find the sum of all positive integers <var>n</var> <img src='images/symbol_le.gif' width='10' height='12' alt='&le;' border='0' style='vertical-align:middle;' /> 10<sup>18</sup> for which <var>p</var>(<var>n</var>) has the form <var>k</var> + <sup>1</sup>&frasl;<sub>2</sub>, where <var>k</var> is an integer.</p>
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