
Combinatoric selections
Problem 53
Published on Friday, 26th September 2003, 06:00 pm; Solved by 28891There are exactly ten ways of selecting three from five, 12345:
123, 124, 125, 134, 135, 145, 234, 235, 245, and 345
In combinatorics, we use the notation, 5C3 = 10.
In general,
| nCr = | n! r!(n |
,where r |
It is not until n = 23, that a value exceeds one-million: 23C10 = 1144066.
How many, not necessarily distinct, values of nCr, for 1
n
100, are greater than one-million?