Move Project Euler under puzzles.
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38
puzzles/project_euler/p006_SumSquareDiff.cpp
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38
puzzles/project_euler/p006_SumSquareDiff.cpp
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/* Check cf5-opt.vim defs.
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VIM: let g:lcppflags="-std=c++11 -O2 -pthread"
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VIM: let g:wcppflags="/O2 /EHsc /DWIN32"
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*/
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#include <iostream>
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/*
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Sum square difference
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Problem 6
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The sum of the squares of the first ten natural numbers is,
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1^2 + 2^2 + ... + 10^2 = 385
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The square of the sum of the first ten natural numbers is,
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(1 + 2 + ... + 10)^2 = 55^2 = 3025
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Hence the difference between the sum of the squares of the first ten natural
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numbers and the square of the sum is 3025 - 385 = 2640.
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Find the difference between the sum of the squares of the first one hundred
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natural numbers and the square of the sum.
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Solution:
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25164150
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*/
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int main ( void )
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{
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const long long n = 100;
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long long s = n*(n+1)/2;
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s*=s;
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for ( long long i = 1; i <= n; ++i )
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s-=i*i;
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std::cout << s << std::endl;
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return 0;
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}
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