## Connectedness of a network.

### Problem 186

Published on Saturday, 15th March 2008, 05:00 am; Solved by 1471

Here are the records from a busy telephone system with one million users:

RecNr | Caller | Called
1 | 200007 | 100053
2 | 600183 | 500439
3 | 600863 | 701497
... | ... | ...

The telephone number of the caller and the called number in record n are Caller(n) = S2n-1 and Called(n) = S2n where S1,2,3,... come from the "Lagged Fibonacci Generator":

For 1 k 55, Sk = [100003 - 200003k + 300007k3] (modulo 1000000)
For 56 k, Sk = [Sk-24 + Sk-55] (modulo 1000000)

If Caller(n) = Called(n) then the user is assumed to have misdialled and the call fails; otherwise the call is successful.

From the start of the records, we say that any pair of users X and Y are friends if X calls Y or vice-versa. Similarly, X is a friend of a friend of Z if X is a friend of Y and Y is a friend of Z; and so on for longer chains.

The Prime Minister's phone number is 524287. After how many successful calls, not counting misdials, will 99% of the users (including the PM) be a friend, or a friend of a friend etc., of the Prime Minister?