## Pythagorean odds

### Problem 285

Published on Saturday, 3rd April 2010, 05:00 am; Solved by 685

Albert chooses a positive integer k, then two real numbers a, b are randomly chosen in the interval [0,1] with uniform distribution.
The square root of the sum (k·a+1)2+ (k·b+1)2 is then computed and rounded to the nearest integer. If the result is equal to k, he scores k points; otherwise he scores nothing.

For example, if k= 6, a= 0.2 and b= 0.85, then (k·a+1)2+ (k·b+1)2= 42.05.
The square root of 42.05 is 6.484... and when rounded to the nearest integer, it becomes 6.
This is equal to k, so he scores 6 points.

It can be shown that if he plays 10 turns with k= 1, k= 2, ..., k= 10, the expected value of his total score, rounded to five decimal places, is 10.20914.

If he plays 105 turns with k= 1, k= 2, k= 3, ..., k= 105, what is the expected value of his total score, rounded to five decimal places?